(C) According to Gauss's Law,the total electric flux $\phi$ through a closed surface is given by $\phi = \frac{q_{\text{enclosed}}}{\epsilon_0}$.In th

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(C) According to Gauss's Law,the total electric flux $\phi$ through a closed surface is given by $\phi = \frac{q_{\text{enclosed}}}{\epsilon_0}$.In the given figure,the charges enclosed by the Gaussian surface are $q_1$ and $q_2$. Therefore,the flux depends only on $q_1$ and $q_2$. Thus,the Assertion is correct.However,the electric field at any point on the Gaussian surface is the vector sum of the electric fields produced by all the charges present in the space ($q_1, q_2, q_3$ and $q_4$). Therefore,the electric field at any point on the surface depends on all the charges,not just the enclosed ones. Thus,the Reason is incorrect.

Class 12 Physics Electric Charges and Fields Electric Field Lines, Electric Flux and Gauss's Law

Easy

Assertion: Four point charges $q_1, q_2, q_3$ and $q_4$ are as shown in the figure. The flux over the shown Gaussian surface depends only on charges $q_1$ and $q_2$.
Reason: Electric field at all points on the Gaussian surface depends only on charges $q_1$ and $q_2$.

AIIMS 2012 All AIIMS

A
If both Assertion and Reason are correct and Reason is the correct explanation of Assertion.
B
If both Assertion and Reason are correct,but Reason is not the correct explanation of Assertion.
C
If Assertion is correct but Reason is incorrect.
D
If both the Assertion and Reason are incorrect.

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Electric Charges and Fields

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Electric Field Lines, Electric Flux and Gauss's Law

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$(4)$ Electric field lines exist in reality.

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DifficultJEE MAIN 2019

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Assertion: Four point charges $q_1, q_2, q_3$ and $q_4$ are as shown in the figure. The flux over the shown Gaussian surface depends only on charges $q_1$ and $q_2$.Reason: Electric field at all points on the Gaussian surface depends only on charges $q_1$ and $q_2$.

Similar Questions

If some charge is given to a solid metallic sphere,the field inside remains zero and by Gauss's law all the charge resides on the surface. Now,suppose that Coulomb's force between two charges varies as $1 / r^{3}$. Then,for a charged solid metallic sphere

Consider a cube of side length '$a$' centered at the origin. It is enclosed by three fixed point charges: $(-q)$ at $(0, -a/4, 0)$,$(+3q)$ at $(0, 0, 0)$,and $(-q)$ at $(0, a/4, 0)$. Choose the correct option.

$A$ charge $Q \ C$ is placed at the center of a cube. If $\varepsilon_0$ is the permittivity of vacuum,then the flux through one face and two opposite faces of the cube is respectively:

Shown in the figure is a shell made of a conductor. It has inner radius $a$ and outer radius $b$,and carries a total charge $Q$. At its centre is a dipole $\vec{P}$ as shown. In this case,

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Assertion: Four point charges $q_1, q_2, q_3$ and $q_4$ are as shown in the figure. The flux over the shown Gaussian surface depends only on charges $q_1$ and $q_2$.
Reason: Electric field at all points on the Gaussian surface depends only on charges $q_1$ and $q_2$.