Assertion: A positive charge particle is plac | vedclass

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(D) For any closed surface enclosing a net charge of $0$, the total electric flux through the surface is $0$ according to Gauss's Law $(\Phi = \oint E

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If both the Assertion and Reason are incorrect.

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(D) For any closed surface enclosing a net charge of $0$, the total electric flux through the surface is $0$ according to Gauss's Law $(\Phi = \oint E \cdot dA = q_{enclosed} / \epsilon_0 = 0)$.This means the number of electric field lines entering the surface must exactly equal the number of lines leaving the surface.Therefore, the Assertion is incorrect because the number of lines terminating on the sphere cannot be more than those emerging from it.The Reason is correct because, due to electrostatic induction, the side of the conductor closer to the positive point charge develops a negative induced charge, which has the highest surface charge density in magnitude.Since the Assertion is incorrect and the Reason is correct, the correct choice is $D$ (based on standard logic for this specific question type).

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