Assign A,B,C,D from given type of reaction. X | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The given reaction is: $3XeF_4 + 6H_2O \longrightarrow Xe + 2XeO_3 + 12HF + 1.5O_2$. In this reaction,the oxidation state of $Xe$ in $XeF_4$ is $+

Vedclass · Accepted Answer

$A$. for disproportionation reaction.

Vedclass · Answer

(A) The given reaction is: $3XeF_4 + 6H_2O \longrightarrow Xe + 2XeO_3 + 12HF + 1.5O_2$. In this reaction,the oxidation state of $Xe$ in $XeF_4$ is $+4$. In the products,$Xe$ is in $0$ oxidation state (in $Xe$) and $+6$ oxidation state (in $XeO_3$). Since the same element $(Xe)$ is simultaneously oxidized (from $+4$ to $+6$) and reduced (from $+4$ to $0$),this is a disproportionation reaction. Therefore,the correct assignment is $A$.

Assign $A$,$B$,$C$,$D$ from given type of reaction. $XeF_4 + H_2O \longrightarrow Xe + XeO_3 + HF + O_2$

Similar Questions

When $P_4$ reacts with caustic soda,the products are $PH_3$ and $NaH_2PO_2$. This reaction is an example of

In the reaction $P_4 + 3KOH + 3H_2O \to PH_3 + 3KH_2PO_2$,phosphorus is .........

Disproportionation of $1 \ mol$ of $MnO_4^{2-}$ in neutral aqueous solution results in which of the following?

What will $1 \ mol$ of $MnO_4^{2-}$ produce upon disproportionation in a neutral aqueous medium?

The reaction that takes place when $Cl_2$ gas is passed through concentrated $NaOH$ solution is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module