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(B) The reaction between potassium dichromate $(K_2Cr_2O_7)$ and sodium hydroxide $(NaOH)$ is as follows:$K_2Cr_2O_7 + 2NaOH \longrightarrow 2K_2CrO_4

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for coloured solution.

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(B) The reaction between potassium dichromate $(K_2Cr_2O_7)$ and sodium hydroxide $(NaOH)$ is as follows:$K_2Cr_2O_7 + 2NaOH \longrightarrow 2K_2CrO_4 + H_2O$In this reaction,the orange-coloured dichromate ion $(Cr_2O_7^{2-})$ is converted into the yellow-coloured chromate ion $(CrO_4^{2-})$.Since $K_2CrO_4$ is soluble in water,it forms a yellow-coloured solution.Therefore,the correct classification for this reaction is for a coloured solution.

Assign $A, B, C, D$ from the given type of reaction.
$K_2Cr_2O_7 + 2NaOH \longrightarrow 2K_2CrO_4 + H_2O$
Identify the nature of the product $CrO_4^{2-}$ formed in the reaction.

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Assign $A, B, C, D$ from the given type of reaction.$K_2Cr_2O_7 + 2NaOH \longrightarrow 2K_2CrO_4 + H_2O$Identify the nature of the product $CrO_4^{2-}$ formed in the reaction.