At $143 \ K$,the reaction of $XeF_4$ with $O_2F_2$ produces a xenon compound $Y$. The total number of lone pair$(s)$ of electrons present on the whole molecule of $Y$ is . . . . .
- A$19$
- B$20$
- C$25$
- D$30$
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View Solution$A$ xenon compound '$A$' upon partial hydrolysis gives $XeO_{2}F_{2}$. The number of lone pairs of electrons present in compound $A$ is ....... . (Round off to the nearest integer)
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