What is the oxidation state of xenon in xenon | vedclass

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Question

(C) The chemical formula for xenon monooxytetrafluoride is $XeOF_4$. Let the oxidation state of xenon be $x$. The oxidation state of oxygen is $-2$ an

Vedclass · Accepted Answer

$6$

Vedclass · Answer

(C) The chemical formula for xenon monooxytetrafluoride is $XeOF_4$. Let the oxidation state of xenon be $x$. The oxidation state of oxygen is $-2$ and the oxidation state of fluorine is $-1$. Setting the sum of oxidation states equal to the charge of the molecule $(0)$: $x + (-2) + 4(-1) = 0$ $x - 2 - 4 = 0$ $x - 6 = 0$ $x = +6$. Therefore,the oxidation state of xenon in $XeOF_4$ is $+6$.

What is the oxidation state of xenon in xenon monooxytetrafluoride?

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