At 27^{circ} C temperature,the mean kinetic e | vedclass

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(C) The mean kinetic energy $(E)$ of an ideal gas is directly proportional to its absolute temperature ($T$ in Kelvin),given by the formula $E = \frac

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$2 E_1$

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(C) The mean kinetic energy $(E)$ of an ideal gas is directly proportional to its absolute temperature ($T$ in Kelvin),given by the formula $E = \frac{3}{2} k_B T$.Therefore,$E \propto T$.Given initial temperature $T_1 = 27^{\circ} C = 27 + 273 = 300 \ K$.Given final temperature $T_2 = 327^{\circ} C = 327 + 273 = 600 \ K$.Using the proportionality ratio: $\frac{E_2}{E_1} = \frac{T_2}{T_1}$.Substituting the values: $E_2 = E_1 	imes \frac{600}{300}$.$E_2 = 2 E_1$.

At $27^{\circ} C$ temperature,the mean kinetic energy of the atoms of an ideal gas is $E_1$. If the temperature is increased to $327^{\circ} C$,then the mean kinetic energy of the atoms will be

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