At T(K),100 L of dry oxygen is present in a | vedclass

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(D) The chemical reaction for the formation of ozone from oxygen is: $3O_2(g) \rightarrow 2O_3(g)$.Let the initial volume of $O_2$ be $100 \ L$.Let th

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$40$

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(D) The chemical reaction for the formation of ozone from oxygen is: $3O_2(g) ightarrow 2O_3(g)$.Let the initial volume of $O_2$ be $100 \ L$.Let the volume of $O_2$ reacted be $3x \ L$.According to the stoichiometry,the volume of $O_3$ formed will be $2x \ L$.The remaining volume of $O_2$ is $(100 - 3x) \ L$.Given that the final volumes of $O_2$ and $O_3$ are equal:$100 - 3x = 2x$$100 = 5x$$x = 20 \ L$.The volume of ozone formed is $2x = 2 	imes 20 = 40 \ L$.

At $T(K)$,$100 \ L$ of dry oxygen is present in a sealed container. It is subjected to silent electric discharge,till the volumes of oxygen and ozone become equal. What is the volume (in litres) of ozone formed at $T(K)$?

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