At NTP,the mass of one litre of air is 1.293 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) At $NTP$ (Normal Temperature and Pressure),the standard conditions are:Pressure $P = 1.013 	imes 10^5 \; Pa$Temperature $T = 273.15 \; K$Volume $

Vedclass · Accepted Answer

$0.29$

Vedclass · Answer

(A) At $NTP$ (Normal Temperature and Pressure),the standard conditions are:Pressure $P = 1.013 	imes 10^5 \; Pa$Temperature $T = 273.15 \; K$Volume $V = 1 \; L = 10^{-3} \; m^3$Mass $m = 1.293 \; g = 1.293 	imes 10^{-3} \; kg$Using the ideal gas equation $PV = m R_{specific} T$,where $R_{specific}$ is the specific gas constant:$R_{specific} = \frac{PV}{mT}$$R_{specific} = \frac{(1.013 	imes 10^5 \; Pa) 	imes (10^{-3} \; m^3)}{(1.293 	imes 10^{-3} \; kg) 	imes (273.15 \; K)}$$R_{specific} \approx \frac{101.3}{0.3531} \approx 287 \; J/(kg \cdot K)$Since the question asks for the unit $J/(K \cdot g)$,we convert $kg$ to $g$:$R_{specific} = \frac{287 \; J}{1000 \; g \cdot K} = 0.287 \; J/(K \cdot g) \approx 0.29 \; J/(K \cdot g)$.

At $NTP$,the mass of one litre of air is $1.293 \; g$. The value of the specific gas constant will be ...... $J/(K \cdot g)$.

Similar Questions

Two spheres are connected to each other as shown in the figure. The volume of sphere $I$ is twice the volume of sphere $II$. They contain an ideal gas at temperatures $100 K$ and $200 K$,respectively. If the mass of the gas in sphere $I$ is $m$,what is the mass of the gas in sphere $II$?

Write the standard temperature and pressure $(STP)$ values.

The equation of state for $5 \ g$ of oxygen gas at pressure $P$,volume $V$,and temperature $T$ is given by:

$A$ fixed amount of gas has a volume $V$ at constant pressure. If the temperature of the gas is increased such that the $v_{rms}$ of the molecules doubles,then its new volume will be .......

$A$ pressure cooker contains air at $1$ atm and $30^\circ C$. If the safety valve of the cooker blows when the inside pressure $\ge 3$ atm,then the maximum temperature of the air inside the cooker can be .... $^\circ C$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module