At a certain temperature,if pK_w = 12.60,then | vedclass

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(C) Given $pK_w = 12.60$,so $K_w = [H^{+}][OH^{-}] = 10^{-12.60}$.For a neutral solution,$[H^{+}] = [OH^{-}]$.Thus,$[H^{+}]^2 = 10^{-12.60} = 10^{0.40

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$[OH^{-}] < 5 	imes 10^{-7} \ M$

Vedclass · Answer

(C) Given $pK_w = 12.60$,so $K_w = [H^{+}][OH^{-}] = 10^{-12.60}$.For a neutral solution,$[H^{+}] = [OH^{-}]$.Thus,$[H^{+}]^2 = 10^{-12.60} = 10^{0.40} 	imes 10^{-13} \approx 2.51 	imes 10^{-13} \approx 0.251 	imes 10^{-12}$.Calculating $[H^{+}] = \sqrt{10^{-12.60}} = 10^{-6.30} \approx 5.01 	imes 10^{-7} \ M$.For an acidic solution,$[H^{+}] > 5.01 	imes 10^{-7} \ M$.Since $[H^{+}][OH^{-}] = 10^{-12.60}$,if $[H^{+}] > 5.01 	imes 10^{-7} \ M$,then $[OH^{-}] < 5.01 	imes 10^{-7} \ M$.

At a certain temperature,if $pK_w = 12.60$,then which of the following is correct for an acidic solution?

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