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(A) The root mean square speed $(v_{rms})$ of gas molecules is given by the formula $v_{rms} = \sqrt{\frac{3RT}{M}}$,where $R$ is the universal gas co

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Light gas

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(A) The root mean square speed $(v_{rms})$ of gas molecules is given by the formula $v_{rms} = \sqrt{\frac{3RT}{M}}$,where $R$ is the universal gas constant,$T$ is the absolute temperature,and $M$ is the molar mass of the gas.From this relation,it is clear that $v_{rms} \propto \frac{1}{\sqrt{M}}$.Therefore,for a given temperature $T$,the speed of gas molecules is inversely proportional to the square root of their molar mass.As a result,a lighter gas (with a smaller molar mass $M$) will have a higher speed compared to a heavier gas.

At a given temperature,which gas has a higher speed: light or heavy?

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