At resonance,the value of current in a series $L-C-R$ circuit is: (Symbols have their usual meanings.)

  • A
    $\frac{e_0}{R}$
  • B
    $\frac{e_0}{\sqrt{R^2+\omega^2 C^2}}$
  • C
    $e_0\left[R^2+\left(\omega L+\frac{1}{\omega C}\right)^2\right]$
  • D
    $\frac{e_0}{\sqrt{R^2+\omega^2 L^2}}$

Explore More

Similar Questions

On which factor does the sharpness of resonance depend?

In a non-resonant $LCR$ series circuit,what will be the nature of the circuit for frequencies higher than the resonance frequency?

$A$ resistor of resistance $R$, an inductor of inductive reactance $2R$, and a capacitor of capacitive reactance $X_C$ are connected in series to an $A.C.$ source. If the series $LCR$ circuit is in resonance, then the power factor of the circuit and the value $X_C$ are respectively:

With a gradual increase in the frequency of an $A.C.$ supply,the impedance of an $LCR$ series circuit

With the gradual increase in frequency of an $A.C.$ source,the impedance of an $LCR$ series circuit

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo