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(A) The impedance $Z$ of an $LCR$ series circuit is given by $Z = \sqrt{R^2 + (X_L - X_C)^2}$,where $X_L = 2\pi fL$ and $X_C = \frac{1}{2\pi fC}$.As t

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first decreases,becomes minimum and then increases.

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(A) The impedance $Z$ of an $LCR$ series circuit is given by $Z = \sqrt{R^2 + (X_L - X_C)^2}$,where $X_L = 2\pi fL$ and $X_C = \frac{1}{2\pi fC}$.As the frequency $f$ increases,$X_L$ increases and $X_C$ decreases.At low frequencies,$X_C$ dominates,so $Z$ decreases as $f$ increases.At the resonant frequency $f_0 = \frac{1}{2\pi \sqrt{LC}}$,$X_L = X_C$,making the impedance $Z$ minimum and equal to $R$.As the frequency increases beyond $f_0$,$X_L$ dominates,causing the impedance $Z$ to increase again.Therefore,the impedance first decreases,reaches a minimum value at resonance,and then increases.

List-$I$	List-$II$
$(a)$ $\omega L > \frac{1}{\omega C}$	$(i)$ Current is in phase with $emf$
$(b)$ $\omega L = \frac{1}{\omega C}$	$(ii)$ Current lags behind the applied $emf$
$(c)$ $\omega L < \frac{1}{\omega C}$	$(iii)$ Maximum current occurs
$(d)$ Resonant frequency	$(iv)$ Current leads the $emf$

With the gradual increase in frequency of an $A.C.$ source,the impedance of an $LCR$ series circuit

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