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(C) Area of base $= 10 	imes 10 = 100 	ext{ cm}^2$.Perimeter of base $= 4 	imes 10 = 40 	ext{ cm}$.The slant height $(l)$ of the pyramid is calcul

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$360$

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(C) Area of base $= 10 	imes 10 = 100 	ext{ cm}^2$.Perimeter of base $= 4 	imes 10 = 40 	ext{ cm}$.The slant height $(l)$ of the pyramid is calculated using the height $(h = 12 	ext{ cm})$ and half the side of the base $(a/2 = 5 	ext{ cm})$:$l = \sqrt{(a/2)^2 + h^2} = \sqrt{5^2 + 12^2} = \sqrt{25 + 144} = \sqrt{169} = 13 	ext{ cm}$.Curved Surface Area $(C.S.A.)$ of the pyramid $= \frac{1}{2} 	imes 	ext{Perimeter of base} 	imes 	ext{slant height}$$C.S.A. = \frac{1}{2} 	imes 40 	imes 13 = 20 	imes 13 = 260 	ext{ cm}^2$.Total Surface Area $(T.S.A.)$ $= C.S.A. + 	ext{Area of base}$$T.S.A. = 260 	ext{ cm}^2 + 100 	ext{ cm}^2 = 360 	ext{ cm}^2$.

The base of a right pyramid is a square of side $10 \text{ cm}$. If the height of the pyramid is $12 \text{ cm}$,then its total surface area is ....... $\text{cm}^2$.

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