Block A of mass 4 ; kg is to be kept at rest | vedclass

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(A) For the block to be in equilibrium, the net force acting on it must be zero.In the vertical direction, the upward component of the applied force $

Vedclass · Accepted Answer

$40$

Vedclass · Answer

(A) For the block to be in equilibrium, the net force acting on it must be zero.In the vertical direction, the upward component of the applied force $F$ must balance the weight of the block $(mg)$.The vertical component of the force is $F \sin 45^{\circ}$.Equating the vertical forces: $F \sin 45^{\circ} = mg$.Given $m = 4 \; kg$ and $g = 10 \; m/s^2$, so $mg = 4 	imes 10 = 40 \; N$.Substituting the values: $F 	imes \frac{1}{\sqrt{2}} = 40$.Therefore, $F = 40 \sqrt{2} \; N$.

Block $A$ of mass $4 \; kg$ is to be kept at rest against a smooth vertical wall by applying a force $F$ as shown in the figure. The force required is .......... $N$ $\left(g = 10 \; m/s^2\right)$. (in $\sqrt{2}$)

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