Bulk modulus of water is 2 times 10^9 N/m^2. | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The formula for Bulk modulus $(K)$ is given by $K = -\frac{p}{\Delta V / V}$,where $p$ is the change in pressure and $\Delta V/V$ is the volumetri

Vedclass · Accepted Answer

$2 	imes 10^6$

Vedclass · Answer

(C) The formula for Bulk modulus $(K)$ is given by $K = -\frac{p}{\Delta V / V}$,where $p$ is the change in pressure and $\Delta V/V$ is the volumetric strain.Since we are increasing the volume,the pressure change $p$ acts as a negative pressure (tensile stress).Given: $K = 2 	imes 10^9 \ N/m^2$ and $\frac{\Delta V}{V} = 0.1 \% = 0.1 / 100 = 10^{-3}$.Substituting the values into the formula: $2 	imes 10^9 = \frac{p}{10^{-3}}$.Therefore,$p = 2 	imes 10^9 	imes 10^{-3} = 2 	imes 10^6 \ N/m^2$.

Bulk modulus of water is $2 \times 10^9 \ N/m^2$. The pressure required to increase the volume of water by $0.1 \%$ in $N/m^2$ is:

Similar Questions

What is the process of transferring cell cultures from an old medium to a new medium called?

Which of the following is Potash Alum?

$\sqrt{3} \operatorname{cosec} 20^{\circ} - \sec 20^{\circ}$ is equal to

The coefficient of $x^5$ in the expansion of $(1+x^2)^5(1+x)^4$ is:

In the given branch $AB$ of a circuit, a current $I = (10t + 5) \, A$ is flowing, where $t$ is time in seconds. At $t = 0$, the potential difference between points $A$ and $B$ $(V_A - V_B)$ is......$V$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module