By Remainder Theorem,find the remainder when | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) According to the Remainder Theorem,if a polynomial $p(x)$ is divided by $(x - a)$,the remainder is $p(a)$.Given $g(x) = x + 1$,we set $g(x) = 0$ t

Vedclass · Accepted Answer

$0$

Vedclass · Answer

(B) According to the Remainder Theorem,if a polynomial $p(x)$ is divided by $(x - a)$,the remainder is $p(a)$.Given $g(x) = x + 1$,we set $g(x) = 0$ to find the value of $x$:$x + 1 = 0 \Rightarrow x = -1$.Now,substitute $x = -1$ into $p(x)$:$p(-1) = (-1)^{3} - 2(-1)^{2} - 4(-1) - 1$$p(-1) = -1 - 2(1) + 4 - 1$$p(-1) = -1 - 2 + 4 - 1$$p(-1) = -4 + 4 = 0$.Therefore,the remainder is $0$.

By Remainder Theorem,find the remainder when $p(x)$ is divided by $g(x)$,where $p(x) = x^{3} - 2x^{2} - 4x - 1$ and $g(x) = x + 1$.

Similar Questions

Write the following cube in expanded form:
$(3x + 2y)^3$

Factorise $10 x^{2}-x-24$ by splitting the middle term.

Expand $(x+5y)(x-5y)$.

Factorise:
$a^{3}-8 b^{3}-64 c^{3}-24 a b c$

Factorise $25 x^{2}+9 y^{2}+64+30 x y-48 y-80 x$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module