By using the fact g.c.d.(a, b) times l.c.m.(a | vedclass

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(A) Given numbers are $a = 96$ and $b = 404$.First,find the prime factorization of $96$ and $404$:$96 = 2^5 	imes 3$$404 = 2^2 	imes 101$The $g.c.d.

Vedclass · Accepted Answer

$9696$

Vedclass · Answer

(A) Given numbers are $a = 96$ and $b = 404$.First,find the prime factorization of $96$ and $404$:$96 = 2^5 	imes 3$$404 = 2^2 	imes 101$The $g.c.d.(96, 404)$ is the product of the smallest power of each common prime factor:$g.c.d.(96, 404) = 2^2 = 4$.Using the formula $g.c.d.(a, b) 	imes l.c.m.(a, b) = a 	imes b$:$4 	imes l.c.m.(96, 404) = 96 	imes 404$$l.c.m.(96, 404) = \frac{96 	imes 404}{4}$$l.c.m.(96, 404) = 96 	imes 101 = 9696$.

By using the fact $g.c.d.(a, b) \times l.c.m.(a, b) = a \times b$,find $l.c.m.(96, 404)$.

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