Calcium phosphide reacts with water to form C | vedclass

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Question

(C) Calcium phosphide reacts with water to form calcium hydroxide and phosphine $(PH_3)$: $Ca_3P_2 + 6H_2O \longrightarrow 3Ca(OH)_2 + 2PH_3$ Here,$X$

Vedclass · Accepted Answer

$Cu_3P_2$

Vedclass · Answer

(C) Calcium phosphide reacts with water to form calcium hydroxide and phosphine $(PH_3)$: $Ca_3P_2 + 6H_2O \longrightarrow 3Ca(OH)_2 + 2PH_3$ Here,$X$ is $PH_3$. When phosphine $(PH_3)$ is passed into $CuSO_4$ solution,it reacts to produce a black precipitate of cupric phosphide $(Cu_3P_2)$ and sulfuric acid $(H_2SO_4)$: $3PH_3 + 3CuSO_4 \longrightarrow Cu_3P_2 + 3H_2SO_4$ Thus,$Y$ is $Cu_3P_2$.

Calcium phosphide reacts with water to form $Ca(OH)_2$ and $X$. When $X$ is passed into $CuSO_4$ solution,$Y$ and $H_2SO_4$ are formed. What is $Y$?

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