Calculate Delta H (kJ/mol) for the reaction: | vedclass

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(B) To obtain the target reaction $2FeO_{(s)} + \frac{1}{2} O_{2_{(g)}} 	o Fe_2O_{3_{(s)}}$,we manipulate the given equations:$1$. Multiply equation

Vedclass · Accepted Answer

$-290$

Vedclass · Answer

(B) To obtain the target reaction $2FeO_{(s)} + \frac{1}{2} O_{2_{(g)}} 	o Fe_2O_{3_{(s)}}$,we manipulate the given equations:$1$. Multiply equation $(ii)$ by $2$: $2FeO_{(s)} + 2C_{(graphite)} 	o 2Fe_{(s)} + 2CO_{(g)}$,$\Delta H = 2 	imes 156 = 312 \ kJ/mol$$2$. Reverse equation $(i)$: $2Fe_{(s)} + 3CO_{(g)} 	o Fe_2O_{3_{(s)}} + 3C_{(graphite)}$,$\Delta H = -492 \ kJ/mol$$3$. Use equation $(iii)$: $C_{(graphite)} + O_{2_{(g)}} 	o CO_{2_{(g)}}$,$\Delta H = -393 \ kJ/mol$$4$. Reverse equation $(iv)$ and multiply by $2$: $2CO_{2_{(g)}} 	o 2CO_{(g)} + O_{2_{(g)}}$,$\Delta H = -2 	imes (-283) = 566 \ kJ/mol$Summing these: $(2 	imes 156) - 492 - 393 + 566 = -290 \ kJ/mol$.

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