Calculate the enthalpy of solution of potassium chloride $(KCl)$ if its lattice enthalpy $\Delta_{L} H = 700 \ kJ \ mol^{-1}$ and hydration enthalpy $\Delta_{hyd} H = -680 \ kJ \ mol^{-1}$.
- A$20 \ kJ \ mol^{-1}$
- B$345 \ kJ \ mol^{-1}$
- C$690 \ kJ \ mol^{-1}$
- D$1380 \ kJ \ mol^{-1}$
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