Calculate the entropy change for melting 1 g | vedclass

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(B) The process of melting ice is a phase transition occurring at constant temperature and pressure,which is an equilibrium process.For the process $H

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$0.293$

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(B) The process of melting ice is a phase transition occurring at constant temperature and pressure,which is an equilibrium process.For the process $H_2O_{(s)} ightleftharpoons H_2O_{(l)}$,the entropy change is given by the formula $\Delta S = \frac{\Delta H_{	ext{fusion}}}{T}$.Given,heat of fusion $\Delta H_{	ext{fusion}} = 80 \ J \ g^{-1}$.Temperature $T = 0^{\circ} C = 273 \ K$.Substituting the values,$\Delta S = \frac{80 \ J \ g^{-1}}{273 \ K} \approx 0.293 \ J \ g^{-1} K^{-1}$.

Calculate the entropy change for melting $1 \ g$ of ice at $0^{\circ} C$ in $J \ g^{-1} K^{-1}$,if the heat of fusion of ice at $0^{\circ} C$ is $80 \ J \ g^{-1}$.

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