Calculate the molality of a solution of a non-volatile solute if the boiling point of the solution and the molal elevation constant for the solvent are $319.8 \text{ K}$ and $2.5 \text{ K kg mol}^{-1}$ respectively. [Boiling point of pure solvent $= 319.5 \text{ K}$]
- A$0.12 \text{ mol kg}^{-1}$
- B$0.14 \text{ mol kg}^{-1}$
- C$0.17 \text{ mol kg}^{-1}$
- D$0.21 \text{ mol kg}^{-1}$
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$A$ solution containing $2.5 \times 10^{-3} \ kg$ of a solute dissolved in $75 \times 10^{-3} \ kg$ of water boils at $373.535 \ K$. The molar mass of the solute is $..... \ g \ mol^{-1}$. [nearest integer] (Given: $K_b(H_2O) = 0.52 \ K \ kg \ mol^{-1}$,boiling point of water $= 373.15 \ K$)
Calculate the molality of the solution containing a nonvolatile solute if the boiling point elevation of the solution is $0.39 \ K$.
[$K_{b}$ of water $= 0.52 \ K \ kg \ mol^{-1}$]
[$K_{b}$ of water $= 0.52 \ K \ kg \ mol^{-1}$]
The molal elevation constant is the ratio of the elevation of boiling point to the........
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View SolutionThe molal elevation constant is the ratio of elevation in boiling point to:
Calculate the molality of a solution of a nonvolatile solute having a boiling point elevation of $1.89 \ K$,if the boiling point elevation constant of the solvent is $3.15 \ K \ kg \ mol^{-1}$. (in $m$)
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