Calculate the mole fraction of solute in the solution if the solution is prepared by dissolving $394 \ g$ of a nonvolatile solute in $622 \ g$ of water at $30^{\circ}C$ (Molar mass of solute $= 342 \ g \ mol^{-1}$).

The volumes of $4\,N\, HCl$ and $10\,N\, HCl$ required to make $1\, L$ of $6\,N\, HCl$ are

$20 \, mL$ of $0.5 \, M \, HCl$ is mixed with $30 \, mL$ of $0.3 \, M \, HCl$. The molarity of the resulting solution is $......... \, M$.

Molarity $(M)$ of an aqueous solution containing $x \ g$ of anhydrous $CuSO_4$ in $500 \ mL$ solution at $32^{\circ} C$ is $2 \times 10^{-1} \ M$. Its molality will be. . . . . .$\times 10^{-3} \ m$ (nearest integer). [Given density of the solution $= 1.25 \ g/mL$.]

Define the following modes of expressing the concentration of a solution: Mass percentage,Molarity,Molality,and Mole fraction. Which of these modes are independent of temperature and why?

The molarity of the solution when $4.9 \ g$ of $H_2SO_4$ is dissolved in $250 \ mL$ of solution is: (in $M$)