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Question

(A) Molar mass of dinitrogen $(N_2) = 28 \,g \,mol^{-1}$.Number of moles of $N_2 = \frac{1.4 \,g}{28 \,g \,mol^{-1}} = 0.05 \,mol$.Number of molecules

Vedclass · Accepted Answer

$4.214 	imes 10^{23}$

Vedclass · Answer

(A) Molar mass of dinitrogen $(N_2) = 28 \,g \,mol^{-1}$.Number of moles of $N_2 = \frac{1.4 \,g}{28 \,g \,mol^{-1}} = 0.05 \,mol$.Number of molecules of $N_2 = 0.05 	imes 6.022 	imes 10^{23} = 3.011 	imes 10^{22}$ molecules.Each $N$ atom has $7$ electrons,so $1$ molecule of $N_2$ has $14$ electrons.Total electrons $= 14 	imes 3.011 	imes 10^{22} = 4.2154 	imes 10^{23}$ electrons.

Calculate the total number of electrons present in $1.4 \,g$ of dinitrogen gas.

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