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(A) The formula for work done against constant external pressure is $W = -P_{	ext{ext}} \Delta V$. Given: $P_{	ext{ext}} = 100 \ kPa = 100 	imes 10

Vedclass · Accepted Answer

$+99 \ kJ$

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(A) The formula for work done against constant external pressure is $W = -P_{	ext{ext}} \Delta V$. Given: $P_{	ext{ext}} = 100 \ kPa = 100 	imes 10^3 \ Pa$,$V_i = 1 \ m^3$,$V_f = 10 \ dm^3 = 0.01 \ m^3$. Change in volume $\Delta V = V_f - V_i = 0.01 \ m^3 - 1 \ m^3 = -0.99 \ m^3$. $W = -(100 	imes 10^3 \ Pa) 	imes (-0.99 \ m^3) = 99,000 \ J = +99 \ kJ$. Since the gas is being compressed,work is done on the system,hence the value is positive.

Calculate the work done during compression of $2 \ mol$ of an ideal gas from a volume of $1 \ m^3$ to $10 \ dm^3$ at $300 \ K$ against a constant external pressure of $100 \ kPa.$

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