Change in entropy for an ideal gas in a reversible isothermal process is given by:

  • A
    $2.303 \, nR \, \log \frac{V_2}{V_1}$
  • B
    $nR \, \ln \frac{V_2}{V_1}$
  • C
    $nR \, \ln \frac{P_1}{P_2}$
  • D
    All of these

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Similar Questions

One mole of a monatomic ideal gas undergoes four thermodynamic processes as shown schematically in the $PV$-diagram below. Among these four processes,one is isobaric,one is isochoric,one is isothermal and one is adiabatic. Match the processes mentioned in List-$I$ with the corresponding statements in List-$II$.
List-$I$ List-$II$
$P$. In process $I$ $1$. Work done by the gas is zero
$Q$. In process $II$ $2$. Temperature of the gas remains unchanged
$R$. In process $III$ $3$. No heat is exchanged between the gas and its surroundings
$S$. In process $IV$ $4$. Work done by the gas is $6 P_0 V_0$

Which of the following equations are correct?
$(A)$ $H = U + PV$
$(B)$ $G = H - TS$
$(C)$ $U = q + W$

Enthalpy of hydrogenation of one mole of benzene to cyclohexane is
$[$Resonance energy of benzene $= -150.4 \ kJ / mol$.
Enthalpy of hydrogenation of cyclohexene $= -119.5 \ kJ / mol$ $]$

Identify the correct statement from the following regarding a chemical reaction.

$1 \ g$ of graphite is burnt in a bomb calorimeter in excess of oxygen at $298 \ K$ and $1 \ atm$ atmospheric pressure according to the equation:
$C \ (graphite) + O_{2(g)} \rightarrow CO_{2(g)}$
During the reaction,the temperature rises from $298 \ K$ to $299 \ K$. If the heat capacity of the bomb calorimeter is $20.7 \ kJ \ K^{-1}$,what is the enthalpy change for the above reaction at $298 \ K$ and $1 \ atm$?

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