Check whether $p(x)$ is a multiple of $g(x)$ or not:
$p(x) = x^{3} - 5x^{2} + 4x - 3, \quad g(x) = x - 2$

(N/A) polynomial $p(x)$ is a multiple of $g(x)$ if and only if $g(x)$ divides $p(x)$ completely,which means the remainder must be $0$.
According to the Remainder Theorem,if $g(x) = x - 2$,we set $x - 2 = 0$,which gives $x = 2$.
Now,we calculate the remainder by evaluating $p(2)$:
$p(2) = (2)^{3} - 5(2)^{2} + 4(2) - 3$
$p(2) = 8 - 5(4) + 8 - 3$
$p(2) = 8 - 20 + 8 - 3$
$p(2) = -7$
Since the remainder is $-7$,which is not equal to $0$,$p(x)$ is not a multiple of $g(x)$.