Coloration of Br_2/CCl_4 will be discharged b | vedclass

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(A) The decolorization of $Br_2/CCl_4$ is a characteristic test for the presence of an unsaturated carbon-carbon double bond $(C=C)$.Cinnamic acid $(C

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Cinnamic acid

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(A) The decolorization of $Br_2/CCl_4$ is a characteristic test for the presence of an unsaturated carbon-carbon double bond $(C=C)$.Cinnamic acid $(C_6H_5CH=CHCOOH)$ contains a carbon-carbon double bond in its side chain.It reacts with bromine in carbon tetrachloride via electrophilic addition to form dibromocinnamic acid,which is colorless.$C_6H_5CH=CHCOOH + Br_2 \xrightarrow{CCl_4} C_6H_5CH(Br)-CH(Br)COOH$Benzoic acid,$o-$phthalic acid,and acetophenone do not contain $C=C$ bonds that undergo this addition reaction under these conditions.

Coloration of $Br_2/CCl_4$ will be discharged by

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