When $CH_2=CH-COOH$ is reduced with $LiAlH_4$,the compound obtained will be:

The product $6-$oxoheptanal is formed by the reductive ozonolysis of:

If the products of ozonolysis are acetone and formaldehyde,what is the starting substance?

$3-$Methylhex$-2-$ene on reaction with $HBr$ in the presence of peroxide forms an addition product $(A)$. The number of possible stereoisomers for '$A$' is $....$.

But$-2-$ene on reaction with alkaline $KMnO_4$ at elevated temperature followed by acidification will give:

$CH_3CH_2CH=CH_2 \xrightarrow{B_2H_6 / H_2O_2, OH^{-}} Z$. What is $Z?$