Compound 'B' is | vedclass

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Question

(B) The reaction sequence is as follows:$1$. The starting material is $2$-isopropyl-$5$-methylphenol (thymol).$2$. Treatment with $NaNO_2/HCl$ perform

Vedclass · Accepted Answer

$4-$amino$-2-$isopropyl$-5-$methylphenol

Vedclass · Answer

(B) The reaction sequence is as follows:$1$. The starting material is $2$-isopropyl-$5$-methylphenol (thymol).$2$. Treatment with $NaNO_2/HCl$ performs electrophilic aromatic substitution (nitrosation) at the para-position relative to the $-OH$ group,forming $A$ (a nitroso compound).$3$. Treatment of the nitroso compound with $NH_4SH$ (ammonium hydrosulfide) reduces the $-NO$ group to an $-NH_2$ group,yielding $B$ as $4$-amino-$2$-isopropyl-$5$-methylphenol.

Compound '$B$' is

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