Compound A (molecular formula C_3H_8O) is tre | vedclass

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Question

(A) is $CH_3CH_2CH_2OH$ (propan$-1-$ol),which on oxidation with acidified $K_2Cr_2O_7$ gives $B$ ($CH_3CH_2CHO$,propanal).$B$ gives a positive Tollen'

Vedclass · Accepted Answer

$CH_3CH_2CH=NNHCONH_2$

Vedclass · Answer

(A) is $CH_3CH_2CH_2OH$ (propan$-1-$ol),which on oxidation with acidified $K_2Cr_2O_7$ gives $B$ ($CH_3CH_2CHO$,propanal).$B$ gives a positive Tollen's test (shining silver mirror),confirming it is an aldehyde.Reaction of propanal $(CH_3CH_2CHO)$ with semicarbazide $(NH_2NHCONH_2)$ in the presence of sodium acetate yields the semicarbazone product $C$.The reaction is: $CH_3CH_2CHO + NH_2NHCONH_2 \rightarrow CH_3CH_2CH=NNHCONH_2 + H_2O$.Therefore,the structure of $C$ is $CH_3CH_2CH=NNHCONH_2$.

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