Compound (x) with molecular formula C_4H_8O g | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The $2,4-DNP$ test is given by aldehydes and ketones (carbonyl compounds). Since the compound does not give a $2,4-DNP$ test,it cannot be an aldeh

Vedclass · Accepted Answer

But$-3-$en$-2-$ol

Vedclass · Answer

(A) The $2,4-DNP$ test is given by aldehydes and ketones (carbonyl compounds). Since the compound does not give a $2,4-DNP$ test,it cannot be an aldehyde or a ketone.The haloform test is given by compounds containing the $CH_3CO-$ group or the $CH_3CH(OH)-$ group.Among the given options:$A$. But$-3-$en$-2-$ol $(CH_2=CH-CH(OH)-CH_3)$ contains the $CH_3CH(OH)-$ group,so it gives a positive haloform test. It is an alcohol,not a carbonyl compound,so it does not give the $2,4-DNP$ test.$B$. Butanal is an aldehyde,so it gives the $2,4-DNP$ test.$C$. Butan$-2-$one is a ketone,so it gives the $2,4-DNP$ test.$D$. Cyclobutanol does not contain the required structural group for the haloform test.Therefore,the correct compound is But$-3-$en$-2-$ol.

Compound $(x)$ with molecular formula $C_4H_8O$ gives a positive haloform test but does not give a $2,4-DNP$ test. The compound is:

Similar Questions

Which of the following is oxidized most easily?

Which one of the following compounds will provide a tertiary alcohol on reaction with excess of $CH_3MgBr$ followed by hydrolysis?

The reaction of ethylene glycol with $PI_3$ gives:

Prof. Sandy Gilbert asked his students to prepare $2$-chloropropane by different methods:
Kaushal's method: $CH_3-CH(OH)-CH_3 \xrightarrow{KCl}$
Preeti's method: $CH_3-CH=CH_2 \xrightarrow{Cl_2 + H_2O}$
Raghav's method: $CH_3-CH(OH)-CH_3 \xrightarrow[Pyridine]{SOCl_2}$

Explain the oxidation of $1^o$,$2^o$,and $3^o$ alcohols with examples.

Vedclass Test Series

Exam Paper Generator

Online Exam Module