Compound 'A' (molecular formula C_3H_8O) is t | vedclass

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Question

(A) $(C_3H_8O)$ is a primary alcohol. Since it oxidizes to an aldehyde $B$ $(C_3H_6O)$ that gives a positive Tollens' test (shining silver mirror),$B$

Vedclass · Accepted Answer

$CH_3CH_2CH=NNHCONH_2$

Vedclass · Answer

(A) $(C_3H_8O)$ is a primary alcohol. Since it oxidizes to an aldehyde $B$ $(C_3H_6O)$ that gives a positive Tollens' test (shining silver mirror),$B$ must be propanal. $CH_3CH_2CH_2OH \xrightarrow{K_2Cr_2O_7/H^{+}} CH_3CH_2CHO$ $A$ (Propan$-1-$ol) $\rightarrow$ $B$ (Propanal) Propanal reacts with semicarbazide $(NH_2NHCONH_2)$ in the presence of sodium acetate to form propanal semicarbazone $(C)$: $CH_3CH_2CHO + NH_2NHCONH_2 \rightarrow CH_3CH_2CH=NNHCONH_2 + H_2O$ Thus,the structure of $C$ is $CH_3CH_2CH=NNHCONH_2$.

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