Compound X on reaction with O_{3} followed by | vedclass

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(D) Ozonolysis of an alkene involves the cleavage of the $C=C$ double bond and the addition of oxygen atoms to each carbon atom of the double bond.For

Vedclass · Accepted Answer

$3-$Methylbut$-1-$ene

Vedclass · Answer

(D) Ozonolysis of an alkene involves the cleavage of the $C=C$ double bond and the addition of oxygen atoms to each carbon atom of the double bond.Formaldehyde is $HCHO$ and $2-$methylpropanal is $(CH_{3})_{2}CHCHO$.By joining the carbonyl carbons of these products by a double bond,we get the structure of the original alkene $X$:$CH_{3}-CH(CH_{3})-CH=O + O=CH_{2} \xrightarrow{Zn/H_{2}O} CH_{3}-CH(CH_{3})-CH=CH_{2} + H_{2}O$The structure $CH_{3}-CH(CH_{3})-CH=CH_{2}$ corresponds to $3-$methylbut$-1-$ene.Therefore,the correct option is $D$.

Compound $X$ on reaction with $O_{3}$ followed by $Zn/H_{2}O$ gives formaldehyde and $2-$methylpropanal as products. The compound $X$ is :

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