Compound (X) [styrene] is subjected to the fo | vedclass

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(B) $1$. Styrene $(C_6H_5CH=CH_2)$ reacts with $Br_2/CHCl_3$ to form styrene dibromide $(C_6H_5CH(Br)CH_2Br)$.$2$. Treatment with excess $NaNH_2$ caus

Vedclass · Accepted Answer

$118$

Vedclass · Answer

(B) $1$. Styrene $(C_6H_5CH=CH_2)$ reacts with $Br_2/CHCl_3$ to form styrene dibromide $(C_6H_5CH(Br)CH_2Br)$.$2$. Treatment with excess $NaNH_2$ causes dehydrohalogenation to form phenylacetylene $(C_6H_5C\equiv CH)$.$3$. Reaction with $CH_3I$ (after deprotonation by $NaNH_2$) yields $1$-phenylprop-$1$-yne $(C_6H_5C\equiv CCH_3)$.$4$. Reduction with $H_2, Na/NH_3(l)$ (Birch-like reduction of alkyne) yields $(E)$-$1$-phenylprop-$1$-ene $(C_6H_5CH=CHCH_3)$.$5$. The molecular formula of the product $(Y)$ is $C_9H_{10}$.$6$. Molar mass $= (9 	imes 12) + (10 	imes 1) = 108 + 10 = 118 	ext{ g mol}^{-1}$.

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