Compounds with high heat of formation are less stable because

  • A
    High temperature is required to synthesise them
  • B
    Molecules of such compounds are distorted
  • C
    It is difficult to synthesis them
  • D
    Energy rich state leads to instability

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Similar Questions

If the enthalpy of formation and enthalpy of solution of $HCl(g)$ are $-92.3 \ kJ/mol$ and $-75.14 \ kJ/mol$ respectively,then find the enthalpy of formation of $Cl^{-}(aq)$. [Assume $\Delta H_{f}(H^{+}) = 0 \ kJ/mol$]

Given that:
$2C_{(s)} + 2O_{2(g)} \to 2CO_{2(g)}$; $\Delta H = -787 \ kJ$
$H_{2(g)} + \frac{1}{2} O_{2(g)} \to H_2O_{(l)}$; $\Delta H = -286 \ kJ$
$C_2H_{2(g)} + \frac{5}{2} O_{2(g)} \to 2CO_{2(g)} + H_2O_{(l)}$; $\Delta H = -1301 \ kJ$
Calculate the heat of formation of acetylene $(C_2H_{2(g)})$ in $kJ$.

Which of the following reactions can be used to define the standard enthalpy of formation of $CO_{2_{(g)}}$?

For $NaCl_{(s)}$,the enthalpy of solution is $4 \ kJ \ mol^{-1}$ and the lattice enthalpy is $790 \ kJ \ mol^{-1}$. What is the hydration enthalpy of $NaCl$?

Which substance has a standard molar enthalpy of formation equal to zero at $298 \ K$?

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