Compute the derivative of f(x) = sin^{2} x. | vedclass

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(B) To find the derivative of $f(x) = \sin^{2} x$,we use the chain rule.Let $u = \sin x$,then $f(x) = u^{2}$.$\frac{df}{dx} = \frac{df}{du} \cdot \fra

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$\sin 2 x$

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(B) To find the derivative of $f(x) = \sin^{2} x$,we use the chain rule.Let $u = \sin x$,then $f(x) = u^{2}$.$\frac{df}{dx} = \frac{df}{du} \cdot \frac{du}{dx}$$\frac{df}{dx} = 2u \cdot \cos x$Substituting $u = \sin x$ back into the equation:$\frac{df}{dx} = 2 \sin x \cos x$Using the trigonometric identity $\sin 2x = 2 \sin x \cos x$,we get:$\frac{df}{dx} = \sin 2x$

Compute the derivative of $f(x) = \sin^{2} x$.

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