(B) The atomic number of Ytterbium $(Yb)$ is $70$. The ground state electronic configuration of neutral $Yb$ is $[Xe] \, 4f^{14} \, 6s^2$. When $Yb$ f

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(B) The atomic number of Ytterbium $(Yb)$ is $70$. The ground state electronic configuration of neutral $Yb$ is $[Xe] \, 4f^{14} \, 6s^2$. When $Yb$ forms the $Yb^{2+}$ ion,it loses two electrons from the outermost $6s$ orbital. Therefore,the electronic configuration of $Yb^{2+}$ is $[Xe] \, 4f^{14}$.