Explore More

Similar Questions

The modulus of the complex number $\frac{(1+i)^2(1+3 i)}{(2-6 i)(2-2 i)}$ is

Let $z = (1+i)(1+2i)(1+3i)\dots(1+ni)$, where $i = \sqrt{-1}$. If $|z|^2 = 44200$, then $n$ is equal to

Find the modulus and argument of the complex number $\frac{1+2i}{1-3i}$.

If $z$ is a complex number such that $z = -\overline{z}$,then $z$:

${\left| {{z_1} + {z_2}} \right|^2} + {\left| {{z_1} - {z_2}} \right|^2}$ is equal to

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo