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(D) Given that $\overrightarrow{r} \cdot \overrightarrow{a} = 0$,this implies that $\overrightarrow{r}$ is perpendicular to $\overrightarrow{a}$.From

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(D) Given that $\overrightarrow{r} \cdot \overrightarrow{a} = 0$,this implies that $\overrightarrow{r}$ is perpendicular to $\overrightarrow{a}$.From $|\overrightarrow{r} 	imes \overrightarrow{b}| = |\overrightarrow{r}| |\overrightarrow{b}|$,we know that $\sin 	heta = 1$,where $	heta$ is the angle between $\overrightarrow{r}$ and $\overrightarrow{b}$. Thus,$\overrightarrow{r}$ is perpendicular to $\overrightarrow{b}$.Similarly,from $|\overrightarrow{r} 	imes \overrightarrow{c}| = |\overrightarrow{r}| |\overrightarrow{c}|$,we conclude that $\overrightarrow{r}$ is perpendicular to $\overrightarrow{c}$.Since $\overrightarrow{r}$ is a non-zero vector perpendicular to $\overrightarrow{a}, \overrightarrow{b},$ and $\overrightarrow{c}$,these three vectors must lie in a plane perpendicular to $\overrightarrow{r}$.Therefore,$\overrightarrow{a}, \overrightarrow{b},$ and $\overrightarrow{c}$ are coplanar.For any three coplanar vectors,their scalar triple product is zero.Thus,$[\overrightarrow{a} \overrightarrow{b} \overrightarrow{c}] = 0$.

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