Consider a glass slab which is silvered at on | vedclass

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(D) When a light ray is incident on the transparent surface of a silvered glass slab,it undergoes refraction,reflection from the silvered surface,and

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(D) When a light ray is incident on the transparent surface of a silvered glass slab,it undergoes refraction,reflection from the silvered surface,and then refraction again as it exits the slab.According to Snell's Law,the angle of incidence $i = 45^{\circ}$ and the angle of refraction $r$ are related by $n_1 \sin(i) = n_2 \sin(r)$. Here,$n_1 = 1$ (air) and $n_2 = 1.5$ (glass).Thus,$\sin(45^{\circ}) = 1.5 \sin(r)$,which gives $\sin(r) = \frac{1}{\sqrt{2} 	imes 1.5} = \frac{1}{1.5 \sqrt{2}}$.Due to the symmetry of the path inside the slab,the ray strikes the silvered surface at angle $r$ and reflects at angle $r$. It then hits the transparent surface at angle $r$ and refracts back into the air at the original angle of incidence $i = 45^{\circ}$.The incident ray makes an angle of $45^{\circ}$ with the normal. The emergent ray also makes an angle of $45^{\circ}$ with the normal on the other side of the normal.The total deviation $\delta$ is the angle between the direction of the incident ray and the emergent ray. Since the incident ray is at $45^{\circ}$ to the left of the normal and the emergent ray is at $45^{\circ}$ to the right of the normal,the angle between them is $45^{\circ} + 45^{\circ} = 90^{\circ}$.

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