Consider a system of two masses and a pulley | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Let $m_1 = 0.8 	ext{ kg}$ and $m_2 = 0.2 	ext{ kg}$. The acceleration is $a = 5 	ext{ m/s}^2$. The coefficient of friction is $\mu = 0.1$.For t

Vedclass · Accepted Answer

$6.4$

Vedclass · Answer

(A) Let $m_1 = 0.8 	ext{ kg}$ and $m_2 = 0.2 	ext{ kg}$. The acceleration is $a = 5 	ext{ m/s}^2$. The coefficient of friction is $\mu = 0.1$.For the $0.2 	ext{ kg}$ block, the tension $T$ pulls it towards the pulley, and the friction force $f_2$ from the $0.8 	ext{ kg}$ block opposes this motion. The normal force on the $0.2 	ext{ kg}$ block is $N_2 = m_2 g = 0.2 	imes 10 = 2 	ext{ N}$.Equation of motion for $m_2$: $T - \mu N_2 = m_2 a \implies T - 0.1 	imes 2 = 0.2 	imes 5 \implies T - 0.2 = 1.0 \implies T = 1.2 	ext{ N}$.For the $0.8 	ext{ kg}$ block, the applied force $F$ acts to the right. The tension $T$ acts to the left. The friction force $f_1$ from the table acts to the left, and the friction force $f_2$ from the $0.2 	ext{ kg}$ block also acts to the left. The normal force from the table is $N_1 = (m_1 + m_2)g = (0.8 + 0.2) 	imes 10 = 10 	ext{ N}$.Equation of motion for $m_1$: $F - T - \mu N_1 - \mu N_2 = m_1 a \implies F - 1.2 - 0.1 	imes 10 - 0.1 	imes 2 = 0.8 	imes 5 \implies F - 1.2 - 1 - 0.2 = 4 \implies F - 2.4 = 4 \implies F = 6.4 	ext{ N}$.

Similar Questions

$A$ block of mass $m$ is placed on the top of another block of mass $M$ as shown in the figure. The coefficient of friction between them is $\mu$. What is the maximum acceleration with which the block $M$ may move so that $m$ also moves along with it?

If force $F$ is increasing with time and at $t = 0, F = 0$,where will slipping first start?

If the acceleration of block $A$ is $2 \, m/s^2$,which is provided by the frictional force from block $B$,then the magnitude of the frictional force applied by block $B$ on block $A$ is ......... $N$.

The maximum value of $F$ which can be applied on the system shown in the figure so that both blocks move together with the same acceleration is ..........

Vedclass Test Series

Exam Paper Generator

Online Exam Module