Consider an amplifier circuit wherein a transistor is used in common emitter mode. The change in collector current and base current respectively are $4 mA$ and $20 \mu A$ when a signal of $40 mV$ is added to the base-emitter voltage. If the load resistance is $10 k\Omega$, then the power gain in the circuit is:
- A$1 \times 10^4$
- B$2 \times 10^5$
- C$8 \times 10^5$
- D$1 \times 10^6$
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View SolutionThe input resistance of a silicon transistor is $100\,\Omega$. Base current is changed by $40\,\mu A$,which results in a change in collector current by $2\,mA$. This transistor is used as a common emitter amplifier with a load resistance of $4\,k\Omega$. The voltage gain of the amplifier is:
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