For a common emitter transistor,if $\frac{I_{C}}{I_{E}}=0.95$,then the current gain is

In case of a bipolar transistor, $\beta = 45$. The potential drop across the collector resistance of $1 \ k\Omega$ is $5 \ V$. The base current is approximately: (in $\mu A$)

In a transistor,if the collector current is $98 \%$ of emitter current,then the ratio of the base and collector currents is

In a common base circuit of a transistor,the amplification factor is $0.95.$ The base current when the emitter current is $2\,mA,$ is ....$mA$

In a $CE$ transistor,when the base current increases by $60 \mu A$,the change in base-emitter voltage is $1.2 \ V$. Then the input resistance is: (in $\Omega$)

When $n-p-n$ transistor is used as an amplifier :