In a $CE$ transistor,when the base current increases by $60 \mu A$,the change in base-emitter voltage is $1.2 \ V$. Then the input resistance is: (in $\Omega$)

The voltage gain of a transistor in common emitter configuration is $160$. The resistances in base and collector sides of the circuit are $1 \text{ k}\Omega$ and $4 \text{ k}\Omega$ respectively. If the change in base current is $100 \mu A$, then the change in output current is:

In a common emitter amplifier of a transistor,if the ratio of the voltage gain and current amplification factor is $4$,then the ratio of the collector and base resistances is

In the symbol of a transistor,the arrow indicates the direction of:

The transfer characteristics [output voltage $(V_o)$ vs input voltage $(V_i)$] for a base-biased transistor in $CE$ configuration are shown in the figure. For using a transistor as a switch,it is used:

In a transistor amplifier,$\beta = 62$,$R_L = 5000\, \Omega$,and the internal resistance of the transistor is $R_i = 500\, \Omega$. The voltage amplification of the amplifier will be: