The transfer characteristics [output voltage $(V_o)$ vs input voltage $(V_i)$] for a base-biased transistor in $CE$ configuration are shown in the figure. For using a transistor as a switch,it is used:

In the given common-emitter circuit, an $npn$ transistor with $\beta = 100$ is connected. What is the output voltage of the amplifier?

Which of these is a unipolar transistor?

In a common emitter amplifier configuration, the current gain is $62$. The collector resistance and input resistance are $5 \text{ k}\Omega$ and $500 \text{ }\Omega$ respectively. If the input voltage is $0.01 \text{ V}$, the output voltage will be (in $V$)

The current gain of a transistor in common emitter configuration is $80$. The resistances in collector and base sides of the circuit are $5 \text{ k}\Omega$ and $1 \text{ k}\Omega$ respectively. If the input voltage is $2 \text{ mV}$, the output voltage is: (in $\text{ V}$)

$A$ $n-p-n$ transistor is connected in common-emitter configuration in which the collector supply is $8\, V$ and the voltage drop across the load resistance of $800\,\Omega$ connected in the collector circuit is $0.8\, V$. If the current amplification factor $\alpha$ is $25/26$,the collector-emitter voltage $V_{CE}$ and the base current $I_B$ will be: