In a transistor,if the collector current is $98 \%$ of emitter current,then the ratio of the base and collector currents is

In an $n-p-n$ transistor amplifier,the collector current is $8 \ mA$. If $80 \%$ of the electrons from the emitter reach the collector,then ($\alpha$ and $\beta$ are current ratios):

For the given bipolar junction transistor,find the approximate value of $I_B$,if $V_{CC} = 9 \ V$,$V_{BB} = 1.5 \ V$,$R_C = 13 \ k\Omega$,$R_E = 17 \ k\Omega$,and $\beta = 100$. (Assume the transistor is in active mode and $V_{BE} = 0.7 \ V$)

$A$ transistor is used in common-emitter mode in an amplifier circuit. When a signal of $10 \, mV$ is added to the base-emitter voltage, the base current changes by $10 \, \mu A$ and the collector current changes by $1.5 \, mA$. The load resistance is $5 \, k\Omega$. The voltage gain of the transistor will be

When $NPN$ transistor is used as an amplifier,

In a $p-n-p$ transistor, the current carriers are