In a $p-n-p$ transistor, the current carriers are

While a collector to emitter voltage is constant in a transistor,the collector current changes by $8.2 \, mA$ when the emitter current changes by $8.3 \, mA$. The value of forward current gain $h_{fe}$ is

$A$ change of $0.04 \ V$ takes place between the base and the emitter when an input signal is connected to the common emitter transistor amplifier. As a result,a $20 \ \mu A$ change takes place in the base current and a change of $2 \ mA$ takes place in the collector current. The input resistance and $AC$ current gain are:

In the $CB$ mode of a transistor, when the collector voltage is changed by $0.5\,V$, the collector current changes by $0.05\,mA$. The output resistance will be....$k\Omega$.

$A$ transistor is connected in common emitter $(CE)$ configuration. The collector supply is $8\ V$ and the voltage drop across a resistor of $800\,\Omega$ in the collector circuit is $0.5\ V$. If the current gain factor $\alpha$ is $0.96$,find the base current in $\mu A$.

Consider an $NPN$ transistor amplifier in common-emitter configuration. The current gain of the transistor is $100$. If the collector current changes by $1\, mA$,what will be the change in emitter current in $mA$?