Consider the coordination compound,[Co(NH_3)_ | vedclass

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(C) In the formation of the coordination complex $[Co(NH_3)_6]^{3+}$,the central metal ion $Co^{3+}$ acts as the Lewis acid because it accepts lone pa

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$Co^{3+}$

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(C) In the formation of the coordination complex $[Co(NH_3)_6]^{3+}$,the central metal ion $Co^{3+}$ acts as the Lewis acid because it accepts lone pairs of electrons from the ligands.$NH_3$ acts as the Lewis base because it donates lone pairs of electrons to the central metal ion.Therefore,the reaction is: $\mathop {Co^{3+}}\limits_{	ext{Lewis acid}} + \mathop {6NH_3}\limits_{	ext{Lewis base}} 	o \mathop {[Co(NH_3)_6]^{3+}}\limits_{	ext{adduct}}$

Consider the coordination compound,$[Co(NH_3)_6]Cl_3$. In the formation of this complex,the species which acts as the Lewis acid is

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